o

x = 5

o

x = 25

o x= V5

o x= V5

**Answer:**

x^2 = 5

x = ±√5

**Answer:**

x = ± [tex]\sqrt{5}[/tex]

**Step-by-step explanation:**

Given

x² = 5 ( take the square root of both sides )

x = ± [tex]\sqrt{5}[/tex] , that is

x = [tex]\sqrt{5}[/tex] or x = - [tex]\sqrt{5}[/tex]

Explain what is the difference between radius

and circumference

**Answer:**

The circumference is the perimeter, specifically the perimeter of a circle. It can be solved by using the following formula:

C = 2πr

C stands for circumference.

π stands for pi, or 3.14 (rounded).

r stands for radius.

The radius is the distance from the center point of the circle to any point on the circle. It is denoted by the variable, *r*, as stated above. It is 1/2 of the diameter.

**Answer:**

the radius is the line from center to perimeter and circumference is the enclosed boundary

**Step-by-step explanation:**

radius- is any of the line segments from a circle or spheres center to its perimeter

circumference- the enclosed boundary a curved geometric figure, especially a circle

Select the two values of x that are roots of this equation.

2x^2+ 1 = 5x

**Answer:**

[tex]\frac{5+\sqrt{17}}{4}[/tex], [tex]\frac{5-\sqrt{17}}{4}[/tex]

**Step-by-step explanation:**

One is asked to find the root of the following equation:

[tex]2x^2+1=5x[/tex]

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

[tex]ax^2+bx+c=0[/tex]

Change the given equation using inverse operations,

[tex]2x^2+1=5x[/tex]

[tex]2x^2-5x+1=0[/tex]

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]

Simplify,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]

[tex]\frac{5(+-)\sqrt{25-8}}{4}[/tex]

[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]

Rewrite,

[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]

[tex]\frac{5+\sqrt{17}}{4}[/tex], [tex]\frac{5-\sqrt{17}}{4}[/tex]

2. sale price $1,089

sales tax rate: 6.25%

**Answer:**

0.0625

**Step-by-step explanation:**

The student looks up the word count on his favorite book, if the book has pages that are 5.5 in. x 6.5 in. and 59,540 words how many pages is the book? (This sentence and picture combine.)

**Answer:**

199 pages

**Step-by-step explanation:**

The average number of words on the page is 300. Because there are 59,540 words and 59540/300 = 198.46 (approximately), there are 199 pages in the book (because the 0.46 pages would be the last page).

Rectangle ABCD translates 4 units down and 2 units to the right to form rectangle A'B'C'D'. The vertices of rectangle ABCD are labeled in alphabetical order going clockwise around the figure. If AB = 3 units and AD = 5 units, what is the length of B'C'? A. 5 units B. 9 units C. 11 units D. 3 units

**Answer:5 units**

**Step-by-step explanation:**

**Answer:**

5

**Step-by-step explanation:**

im bad at math and i need help

I think it would just be n rad n

**Answer:**

n•√n

here is an accurate representation

find the interest where principal (P) Rs 1400 time 2 years ,rate of interest (R) is 5%

**Answer:**

rs140

**Step-by-step explanation:**

I=P×T×R/100

1400×2×5/100

2800×5/100

14000/100

140

**Step-by-step explanation:**

Principle(p)= 1400

time= 2 year

rate= 5%

interest= p×t×r/100

= 1400×2×5/100

= 14000/100

=140

how do you solve 11=t+11.5-t?

**Equations **are represented with the **= sign**. It means **both sides **of the **equation **are **equal**. [tex]11=t+11.5-t[/tex] has **no solution**

Given that:

[tex]11=t+11.5-t[/tex]

Start by collecting like terms

[tex]11-11.5=t-t[/tex]

Evaluate like terms

[tex]-0.5 = 0[/tex]

-0.5 is **not equal **to 0.

Hence, the **equation **has **no solution**

Read more about **equations **at:

https://brainly.com/question/315182

Efetue as divisões indicadas.

a. 3,6 : 1,5

b. 42:0,21

c. 200:0,5

**Answer:**

a)

[tex] \frac{3.6}{1.5} = \frac{36}{15} = 2.4[/tex]

b)

[tex] \frac{42}{0.21} = \frac{4200}{21} = 200[/tex]

c)

[tex] \frac{200}{0.5} = \frac{2000}{5} = 400[/tex]

**I hope I helped you****^****_****^**

Which of the following expressions has a value of 4? A. (16 – 12)2 B. – | – 4 | C. (96 ÷ 8) – 2 to the 3rd power D. 24 – 42

**Answer:**

A. (16-12)

**Step-by-step explanation:**

16-12

Answer

=4

The circumference of a circular garden is 113.04 feet. What is the radius of the garden? Use 3.14 for pie and do not round your answer.

**Answer:**

18 ft

**Step-by-step explanation:**

The circumference of a circle is given by

C = 2 * pi *r

113.04 = 2 ( 3.14) * r

113.04 = 6.28 r

Divide each side by 6.28

113.04/6.28 = 6.28r/6.28

18 =r

Need help as soon as possible pls!!!!!

**Answer:**

probability

**Step-by-step explanation:**

do some division to calculate the probality of landing on a blue 1/3 and add up the numbers.

Write another way to group the factor (3×2)×5 then find the product

**Answer:**

30

**Step-by-step explanation:**

Another way to group the factor would be 3(2×5)

2 times 5 is 10 and then 10 times 3 is 30 so therefore, your answer is 30

Eliana made cookies. She used 8 12 of a cup of flour and 6 12 of a cup of sugar. How much more flour than sugar did Eliana use?

**Answer:**

2/12 the answer

4.

For which discriminant is the graph possible?

A. b2 – 4ac = 0

B. b2 – 4ac = 6

C. b2 – 4ac = –2

**Answer:**

A. b2 – 4ac = 0

**Step-by-step explanation:**

Hey user☺☺

Option a is correct

Because the graph has only one solution.

As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.

Hope this will help☺☺

the quotient of 5+h and n+3

**Answer:**

5+h/n+3

**Step-by-step explanation:**

5+h is numerator

and n+3 is denominator

so you make it a fraction to get the quotient which is 5+h/n+3

Which statement compares the numbers correctly 23.811 > twenty-three and eight hundred eleven thousandths Twenty-three and eight hundred eleven thousandths > 23.811 Twenty-three and eight hundred eleven thousandths < 23.811 Twenty-three and eight hundred eleven thousandths = 23.811

**Answer:**

The correct answer is A.

**Step-by-step explanation:**

The area of a rectangle is 0.8 square units. The length is 3.2 units and the width is x units.

What is the value of x?

x=0.25

x=2.4

x=2.56

x=4

Pls help meeeehhhh I will give brainliesttttt :D

The answer is x=0.25

A new cars salesperson, sold an average of $32,130 per day for the first 4 days she worked. The next 5 days she worked, she sold an average of $31,173. How much did she sell on average per day over the entire time she worked??

**Answer:**

$31,598.33

**Step-by-step explanation:**

she worked 4+5=9 days.

due the total average we need the total of sales and divide it by the length of the observation period (9 days).

how much did she sell in total on the first 4 days ?

well, the average times 4 = 32130×4 = $128520

how much did she sell in total during the following 5 days ?

31173×5 = $155865

so, the daily average is

($128520 + $155865) / 9 =$284385 / 9 = $31,598.33

Which of the choices shows these values arranged from greatest to

least?

.68% 2.43

12/6 2 over -3

23.7 just playing and this not the ans

**Answer:**

vdffdersewsesdfdresweseseseeerswesdsfd

**Step-by-step explanation:**

reterersesdvbvfdderereerereeeewwqwewereddddscdcvvbvfddewww

Yolanda has 3/4 of a cup of sugar. This is 3/5 of what she needs. How much sugar does Yolanda need?

Show your reasoning.

**Answer:**

[tex]1\frac{1}{4}[/tex] cups

**Step-by-step explanation:**

3/4=3/5

2. Solving3/4*1/3=3/5*1/3

1/4 = 1/5

1/4*5=1/5*5

5/4=5/5

5/4= 1 and 1/4 cups

Hope this helped! Please mark brainliest :)

**~~ SUMMER ~~**

is -17 a rational number or irrational number

A rational number is a number that you can write as a fraction of two integers.

-17 = -17/1, -34/2, etc.

-17 is rational.

Irrational numbers, like pi and sqrt(2), cannot be written as a fraction of integers.

-17 = -17/1, -34/2, etc.

-17 is rational.

Irrational numbers, like pi and sqrt(2), cannot be written as a fraction of integers.

**Answer:**

rational

**Step-by-step explanation:**

if a number can be written as a fraction, where p and q are integers and q is a non-zero number

express the trinomial (x+1)(3x+2)

**Answer:**

3x^2+5x+2

**Step-by-step explanation:**

(3x^2)+(2x)+(3x)+(2)

3x^2+5x+2.

**Answer:**

3x²+5x+2

**Step-by-step explanation:**

(x+1)(3x+2)

(3x²)+(2x)+(3x)+(2)

**3x²+5x+2.**

For the equation: – 36 – 4r = -2(-6 + 6r), what is the value of r?

**Answer:**

r = 6

**Step-by-step explanation:**

– 36 – 4r = -2(-6 + 6r)

+36 +36

----------------------------------

-4r = -12r + 48

+12r +12r

----------------------------------

8r = 48

/8 /8

----------------------------------

r = 6

**Answer:**

r = 6

**Step-by-step explanation:**

– 36 – 4r = -2(-6 + 6r)

-36 - 4r = 12 - 12r

-48 - 4r = -12r

-48 = -8r

r = 6

This is line segments.

**Step-by-step explanation:**

[tex]here \: b \: is \: the \: mid \: point \\ so \: ab = bc \\ 10x - 17 = 6x + 11 \\ x \: terms \: togather \\ 10x - 6x = 11 + 17 \\ 4x = 28 \\ x = \frac{28}{4} \\ x = 7 \\ thank \: you[/tex]

So on this line we got points A, B ,and C. These points are all equally distanced from each other. So line AB would have to equal to line BC. And line AB plus line BC would equal line AC.

We are given that line AB is 10x-17, with x as the unknown variable. Line BC is 6x+11. Line AB is equal to Line BC. Now we need to use that information to find x, so we’ll set up the equation.

Line AB=Line BC

10x-17=6x+11

Minus 6x to both sides (like terms)

4x-17=11

Add 17 to both sides (like terms)

4x=28

Divide both sides by 4

x=7

The answer is B. 7

We are given that line AB is 10x-17, with x as the unknown variable. Line BC is 6x+11. Line AB is equal to Line BC. Now we need to use that information to find x, so we’ll set up the equation.

Line AB=Line BC

10x-17=6x+11

Minus 6x to both sides (like terms)

4x-17=11

Add 17 to both sides (like terms)

4x=28

Divide both sides by 4

x=7

The answer is B. 7

What is the period of the function given?

pls

**Answer:**

2. ☑ A [tex]\displaystyle f(x) = tan\:\frac{1}{2}x[/tex]

☐ B [tex]\displaystyle f(x) = tan\:2x[/tex]

☐ C x = [tex]\displaystyle 2tan\:x[/tex]

1. ☐ A [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ B [tex]\displaystyle \pi[/tex]

☑ C [tex]\displaystyle 2\pi[/tex]

**Explanation:**

[tex]\displaystyle \boxed{f(x) = -cot\:(\frac{1}{2}x - \frac{\pi}{2})} \\ \\ y = Acot(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

*OR*

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL *tangent*, *secant*, *cosecant*, and *cotangent* functions have NO amplitudes. Also, keep in mind that although this IS the **tangent** graph, if you plan on writing your equation as a function of *cotangent*, then there WILL be a **horisontal shift**, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cot\:\frac{1}{2}x,[/tex] in which you need to replase "tangent" with "**cotangent**", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the *tangent* graph [photograph on the **left**], accourding to the **horisontal shift formula** above. Also keep in mind that the *−C* gives you the OPPOCITE TERMS OF WHAT THEY *REALLY* ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cotangent graph [photograph on the **right**] is shifted [tex]\displaystyle \pi\:units[/tex] to the left, which means that in order to match the *tangent* graph [photograph on the **left**], we need to shift the graph FORWARD [tex]\displaystyle \pi\:units,[/tex] which means the C-term will be **positive**, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pi} = \frac{\frac{\pi}{2}}{\frac{1}{2}},[/tex] but we are NOT YET DONE. Although we shifted the graph back into position, remember, cotangent is graphed in REVERCE, so we need to insert a **negative**** **in front of the amplitude term, and with that, the cotangent graph of the tangent graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cot\:(\frac{1}{2}x - \frac{\pi}{2}).[/tex] Now, with all that being said, we can move forward. To find the period in this case, you need to take a look at the distanse between each **vertical asymptote**. Now, accourding to this graph, the vertical asymptotes are [tex]\displaystyle -\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of **Deduction**, and doing that will give you [tex]\displaystyle \boxed{2\pi} = \pi + \pi.[/tex] So, the period of this function is [tex]\displaystyle 2\pi.[/tex] Now, you will instantly get the jist of the **horisontal shift** by looking at the above formula. Just keep in mind that the *−C* gives you the OPPOCITE TERMS OF WHAT THEY *REALLY* ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the ** midline** is the centre of your graph, also known as the

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.

1 3/4 divided by 2 3/8

will give brainiest pls help

**Answer: **

[tex]\frac{14}{19}[/tex]

**First:**

Convert any mixed numbers to fractions.

Then your initial equation becomes:

[tex]\frac{7}{4} \div \frac{19}{8}[/tex]

Applying the fractions formula for division:

[tex]= \frac{7 \times 8}{4 \times 19}[/tex]

[tex]= \frac{56}{76}[/tex]

Simplifying 56/76, the answer is:

[tex]\frac{14}{19}[/tex]

**I hope this helps! :)**

**Answer:**

the answer is 14/19

change the mixed numbers to improper fractions then that becomes 7/4 and 19/8 then multiply across 7x8=56 and 19x4=76 that gives you 56/76

Simplifying 56/76,= 14/19

A solid oblique cone with a slant length of 17 units is placed inside an empty cylinder with a congruent base of radius 8 units and a height of 15 units. A solid oblique cone with a slant length of 17 units is inside an empty cylinder with a congruent base of radius 8 units and a height of 15 units. What is the unfilled volume inside the cylinder

I need a picture of the question

**Answer:**

C. 640π cubic units

Question 7

Which graph best represents the solution to the following inequality?

+ 5 > 11

A

16

17

19 20 21 22

23 24 25

O

15

16

17

18 19 20 21 22

23

24 25

c.

10 11

3 4 5

12

15

13 14

D.

8

10

11

12

13

14

15

**Answer:**

D

**Step-by-step explanation:**

x + 5 > 11

is the same as

x > 6

and because it is ">" and not ">=", the solution point is not included.

therefore the right graph is D and not C. an empty little circle means "excluded", while a filled, black circle means "included".

answer needed within one hour :(

**Step-by-step explanation:**

ANGLE ,x=60

B=C(isoscles)

A=B.As sides are equal.

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